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(F)=2F^2-16F+4
We move all terms to the left:
(F)-(2F^2-16F+4)=0
We get rid of parentheses
-2F^2+F+16F-4=0
We add all the numbers together, and all the variables
-2F^2+17F-4=0
a = -2; b = 17; c = -4;
Δ = b2-4ac
Δ = 172-4·(-2)·(-4)
Δ = 257
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{257}}{2*-2}=\frac{-17-\sqrt{257}}{-4} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{257}}{2*-2}=\frac{-17+\sqrt{257}}{-4} $
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